🛠️ JEE🧲 Physics

A small particle of mass \(m\) moves in such a way that its potential energy \(U=\frac{1}{2} m \omega^2 r^2\) where \(\o…

Q1

A small particle of mass \(m\) moves in such a way that its potential energy \(U=\frac{1}{2} m \omega^2 r^2\) where \(\omega\) is constant and \(r\) is the distance of the particle from origin. Assuming Bohr's quantization of momentum and circular orbit, the radius of \(n^{\text {th }}\) orbit will be proportional to:

[JEE Main 2023, 6 Apr (Shift 2)]

a

\(
\sqrt{n}
\)

b

\(
n
\)

c

\(
n^2
\)

d

\(
\frac{1}{n}
\)

🔒
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