🛠️ JEE🧲 Physics

Considering the Bohr model of hydrogen like atoms, the ratio of the ratio of the radius \({5}^{\text{th }}\) orbit of th…

Q1 FREE PREVIEW

Considering the Bohr model of hydrogen like atoms, the ratio of the ratio of the radius \({5}^{\text{th }}\) orbit of the electron in \({\mathrm{Li}}^{2+}\) and \({\mathrm{He}}^{+}\)is;

a

\(\frac{3}{2}\)

b

\(\frac{4}{9}\)

c

\(\frac{9}{4}\)

d

\(\frac{2}{3}\)

✓ Correct answer: d)

\(\frac{2}{3}\)

Explanation

In Bohr's model, radius of \( n^\text{th} \) orbit in hydrogen-like atoms is given by:

\[
r_n \propto \frac{n^2}{Z}
\]

So for 5th orbit:

\[
r_5 \propto \frac{25}{Z}
\]

Now,
For Li\(^{2+}\), \( Z = 3 \Rightarrow r \propto \frac{25}{3} \)
For He\(^{+}\), \( Z = 2 \Rightarrow r \propto \frac{25}{2} \)

Taking ratio:

\[
\frac{r_{Li^{2+}}}{r_{He^+}} = \frac{25/3}{25/2} = \frac{2}{3}
\]

Practice more JEE Physics PYQs

See every question on Atoms, or browse the full JEE question bank.

See all questions on Atoms →