Angular momentum of an electron in a hydrogen atom is \(\frac{3h}{\pi }\), then the energy of the electron is __________…

Bohr quantization: \(L=nℏ=n\frac{h}{2\pi }\) Given: \(L=\frac{3h}{\pi }=6\frac{h}{2\pi }\)

\(\Rightarrow n=6\)

Energy of hydrogen atom:

\({E}_{n}=\frac{-13.6}{{n}^{2}}\)

\(E=\frac{-13.6}{36}\approx -0.38eV\)