JEEPhysics

A small particle of mass \(m\) moves in such a way that its potential energy \(U=\frac{1}{2} m \omega^2 r^2\) where \(\o…

Q1
PYQ

A small particle of mass \(m\) moves in such a way that its potential energy \(U=\frac{1}{2} m \omega^2 r^2\) where \(\omega\) is constant and \(r\) is the distance of the particle from origin. Assuming Bohr's quantization of momentum and circular orbit, the radius of \(n^{\text {th }}\) orbit will be proportional to:

a

\(\sqrt{n}\)

b

\(n\)

c

\(n^2\)

d

\(\frac{1}{n}\)

🔒
Answer & explanation — PYQ Pass

Options are free to see. Unlock the correct answer and full explanation with Pass.

Unlock · ₹149

Practice more JEE Physics PYQs

See every question on Atoms, or browse the full JEE question bank.

See all questions on Atoms →