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A free electron of \(2.6\ eV\) energy collides with a \(H^{+}\) ion. This results in the formation of a hydrogen atom in…

Q1

A free electron of \(2.6\ eV\) energy collides with a \(H^{+}\) ion. This results in the formation of a hydrogen atom in the first excited state and a photon is released. Find the frequency of the emitted photon. \(\left( h = 6.6 \times 10^{- 34}\text{Js} \right)\)

[JEE Main 2021, 26 Aug (Shift 2)]

a

\(1.45 \times 10^{16}\text{ MHz}\)

b

\(0.19 \times 10^{15}\text{ MHz}\)

c

\(1.45 \times 10^{9}\text{ MHz}\)

d

\(9.0 \times 10^{27}\text{ MHz}\)

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