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A series LCR circuit is connected to an alternating source of emf E. The current amplitude at resonant frequency is \(I_…

Q1

A series LCR circuit is connected to an alternating source of emf E. The current amplitude at resonant frequency is \(I_0\). If the value of resistance \(R\) becomes twice of its initial value then amplitude of current at resonance will be

a

\(2{\mathrm{I}}_{0}\)

b

\({I}_{0}\)

c

\(\frac{{\mathrm{I}}_{0}}{\sqrt{2}}\)

d

\(\frac{{I}_{0}}{2}\)

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