An alternating voltage \(V(t)=220 \sin 100 \pi t\) volt is applied to a purely resistive load of \(50 \ \Omega\). The ti…
Q1
An alternating voltage \(V(t)=220 \sin 100 \pi t\) volt is applied to a purely resistive load of \(50 \ \Omega\). The time taken for the current to rise from half of the peak value to the peak value is:
[JEE Main 2024, 30 Jan (Shift 2)]
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