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In a series LCR circuit, the maximum amplitude of current is \({I}_{0}\) when the resistance is \(R\). What will be the …

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In a series LCR circuit, the maximum amplitude of current is \({I}_{0}\) when the resistance is \(R\). What will be the maximum amplitude of current if the resistor is replaced by a resistor of resistance \(R\mathrm{/}2\)?

(Shift II Memory Based)

a

\({I}_{0}\)

b

\(2{I}_{0}\)

c

​\({I}_{0}\mathrm{/}2\)

d

\(2{I}_{0}\mathrm{/}3\)

✓ Correct answer: b)

\(2{I}_{0}\)

Explanation

Current has maximu amplitude at the condition of resonance. In resonance the impedence of the circuit is equal to resistance of the circuit. When resistance is halved, then the maximum amplite of current is doubled.

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