An AC voltage $V=20 \sin 200 \pi t$ is applied to a series LCR circuit which drives a current $I=10 \sin \left(200 \pi t+\frac{\pi}{3}\right)$. The average power dissipated is:

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YESPYQ · Accepted Answer

Correct answer: a) $50 \mathrm{~W}$. ${V}_{rms}=\frac{{V}_{0}}{\sqrt{2}}=\frac{20}{\sqrt{2}},{I}_{rms}=\frac{{I}_{0}}{\sqrt{2}}=\frac{10}{\sqrt{2}}$ $ =\frac{20}{\sqrt{2}}\times \frac{10}{\sqrt{2}}\times \cos \frac{\pi }{3}$ $=\frac{200}{2}\times \frac{1}{2}=50W$

An AC voltage \(V=20 \sin 200 \pi t\) is applied to a series LCR circuit which drives a current \(I=10 \sin \left(200 \p…

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