Let $y=y(x)$ be the solution of the differential equation $\left({x}^{2}+1\right){y}^{'}-2xy=\left({x}^{4}+2{x}^{2}+1\right)\cos x$, $y(0)=1$. Then ${\int }_{-3}^{3}y\left(x\right)dx$ is:

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Let \(y=y(x)\) be the solution of the differential equation \(\left({x}^{2}+1\right){y}^{'}-2xy=\left({x}^{4}+2{x}^{2}+1…

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