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Let \(\mathrm{x}=\mathrm{x}(\mathrm{y})\) be the solution of the differential equation \( y=\left(x-y \frac{d x}{d y}\ri…

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Let \(\mathrm{x}=\mathrm{x}(\mathrm{y})\) be the solution of the differential equation

\(
y=\left(x-y \frac{d x}{d y}\right) \sin \left(\frac{x}{y}\right), y>0 \text { and } x(1)=\frac{\pi}{2} .
\)

Then \(\cos (x(2))\) is equal to :

[JEE Main 2025, 23 Jan (Shift 2)]

a

\(1-2\left(\log _{\mathrm{e}} 2\right)^2\)

b

\(2\left(\log _{\mathrm{e}} 2\right)^2-1\)

c

\(2\left(\log _e 2\right)-1\)

d

\(1-2\left(\log _{\mathrm{e}} 2\right)\)

✓ Correct answer: b)

\(2\left(\log _{\mathrm{e}} 2\right)^2-1\)

Explanation

\(ydy=(xdy-ydx)\sin \left(\frac{x}{y}\right)\\ \frac{dy}{y}=\left(\frac{xdy-ydx}{{y}^{2}}\right)\sin \left(\frac{x}{y}\right)\\ \frac{dy}{y}=\sin \left(\frac{x}{y}\right)d\left(-\frac{x}{y}\right)\\ \Rightarrow \ln y=\cos \frac{x}{y}+C\\ \text{Since},x(1)=\frac{\pi }{2}\\ \Rightarrow 0=\cos \frac{\pi }{2}+C\Rightarrow C=0\\ \Rightarrow \ln y=\cos \frac{x}{y}\\ \text{ but }y=2\\ \Rightarrow \cos \frac{x}{2}=\ln 2\\ \cos x=2{\cos }^{2}\frac{x}{2}-1=2(\ln 2{)}^{2}-1\\\)

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