Let $x=x(y)$ be the solution of the differential equation $y^2 d x+\left(x-\frac{1}{y}\right) d y=0$. If $x(1)=1,$ then $x\left(\frac{1}{2}\right)$ is: [JEE Main 2025, 22 Jan (Shift 1)]

Question

YESPYQ · Accepted Answer

Options are free to see. Unlock the correct answer and full explanation with PYQ Pass.

Let \(x=x(y)\) be the solution of the differential equation \(y^2 d x+\left(x-\frac{1}{y}\right) d y=0\). If \(x(1)=1,\)…

Practice more JEE Maths PYQs