Given below are two statements. Statement-I: One mole of propyne reacts with excess of sodium to liberate half a mole of…
Given below are two statements.
Statement-I: One mole of propyne reacts with excess of sodium to liberate half a mole of hydrogen gas.
Statement-II: Four grams of propyne reacts with sodium amide to liberate ammonia gas which occupies 224 mL at STP.
In the light of above statements, choose most appropriate answer from options given below
[JEE Main 2025, 22 Jan (Shift 1)]
Statement-I is correct but statement-II is incorrect
\({\mathrm{CH}}_{3}-\mathrm{C}\equiv \mathrm{CH}+\mathrm{Na}\to {\mathrm{CH}}_{3}-\mathrm{C}\equiv \overset{-}{\mathrm{C}}\overset{+}{\mathrm{Na}}+\frac{1}{2}{\mathrm{H}}_{2}\\ 1\mathrm{mole}\mathrm{of}\mathrm{propyne}\mathrm{gives}0.5\mathrm{mole}\mathrm{of}\mathrm{hydrogen}\mathrm{gas}\\ {\mathrm{CH}}_{3}-\mathrm{C}\equiv \mathrm{CH}+{\mathrm{NaNH}}_{2}\to {\mathrm{CH}}_{3}-\mathrm{C}\equiv \overset{-}{\mathrm{C}}\overset{+}{\mathrm{Na}}+{\mathrm{NH}}_{3}\\ \mathrm{n}=\frac{4\mathrm{g}}{40\mathrm{g}}=0.1\mathrm{mole}\\ 1\mathrm{mole}\mathrm{occupies}22400\mathrm{ml}\\ \mathrm{So},0.1\mathrm{mole}\mathrm{occupies}2240\mathrm{ml}\)
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