Let $y=y(x)$ be the solution of the differential equation $x \log _e x \frac{d y}{d x}+y=x^2 \log _e x,(x1)$. If $y(2)=2$, then $y(e)$ is equal to [JEE Main 2023, 29 Jan (Shift 2)]

Question

Let $y=y(x)$ be the solution of the differential equation $x \log _e x \frac{d y}{d x}+y=x^2 \log _e x,(x>1)$. If $y(2)=2$, then $y(e)$ is equal to [JEE Main 2023, 29 Jan (Shift 2)]

YESPYQ · Accepted Answer

Options are free to see. Unlock the correct answer and full explanation with PYQ Pass.

Let \(y=y(x)\) be the solution of the differential equation \(x \log _e x \frac{d y}{d x}+y=x^2 \log _e x,(x>1)\). If…

Practice more JEE Maths PYQs

Let \(y=y(x)\) be the solution of the differential equation \(x \log _e x \frac{d y}{d x}+y=x^2 \log _e x,(x&gt;1)\). If…

Practice more JEE Maths PYQs

Let \(y=y(x)\) be the solution of the differential equation \(x \log _e x \frac{d y}{d x}+y=x^2 \log _e x,(x>1)\). If…