Electric potential at a point ' \(P\) ' due to a point charge of \(5\times {10}^{−9}\mathrm{C}\) is \(50 \ V\). The dist…

Electric potential at a point ' \(P\) ' due to a point charge of \(5\times {10}^{−9}\mathrm{C}\) is \(50 \ V\). The distance of ' \(P\) ' from the point charge is:
\(\left(\mathrm{Assume},\frac{1}{4{\mathrm{πε}}_{0}}=9\times {10}^{9}{\mathrm{Nm}}^{2}{\mathrm{C}}^{−2}\right)\)

[JEE Main 2023, 8 Apr (Shift 2)]