Consider a parallel plate capacitor of area A (of each plate) and separation '𝑑' between the plates. If 𝐸 is the electric field and ${\epsilon }_{0}$ is the permittivity of free space between the plates, then potential energy stored in the capacitor is

[JEE Main 2025, 24 Jan (Shift 1)]

Question

Consider a parallel plate capacitor of area A (of each plate) and separation '𝑑' between the plates. If 𝐸 is the electric field and ${\epsilon }_{0}$ is the permittivity of free space between the plates, then potential energy stored in the capacitor is

[JEE Main 2025, 24 Jan (Shift 1)]

YESPYQ · Accepted Answer

Correct answer: d) $\frac{1}{2}{\epsilon }_{0}{E}^{2}Ad$. Energy per unit volume is given by: $\frac{U}{V}=\frac{1}{2}{\epsilon }_{0}{E}^{2}$ Since volume V of the capacitor is $A\times d$, the total energy stored in the capacitor is: $U=\frac{1}{2}{\epsilon }_{0}{E}^{2}\times Ad$

Consider a parallel plate capacitor of area A (of each plate) and separation '𝑑' between the plates. If 𝐸 is the electri…

Practice more JEE Physics PYQs