If $y=y(x)$ is the solution curve of the differential equation ${x}^{2}dy+\left(y-\frac{1}{x}\right)dx=0;x0$, and $y(1)=$ 1 , then $y\left(\frac{1}{2}\right)$ is equal to: [JEE Main 2021, 1 Sep (Shift 2)]

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If $y=y(x)$ is the solution curve of the differential equation ${x}^{2}dy+\left(y-\frac{1}{x}\right)dx=0;x>0$, and $y(1)=$ 1 , then $y\left(\frac{1}{2}\right)$ is equal to: [JEE Main 2021, 1 Sep (Shift 2)]

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If \(y=y(x)\) is the solution curve of the differential equation \({x}^{2}dy+\left(y-\frac{1}{x}\right)dx=0;x>0\), and \…

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