For changing the capacitance of a given parallel plate capacitor, a dielectric material of dielectric constant \(K\) is …
Q1
For changing the capacitance of a given parallel plate capacitor, a dielectric material of dielectric constant \(K\) is used, which has the same area as the plates of the capacitor. The thickness of the dielectric slab is \(\frac{3}{4} d\), where ' \(d\) ' is the separation between the plates of parallel plate capacitor.The new capacitance ( \(C^{\prime}\) ) in terms of original capacitance \(\left( C _0\right)\) is given by the following relation:
[JEE Main 2021, 16 Mar (Shift 1)]
🔒
Answer & explanation — PYQ Pass
Unlock · ₹149
Options are free to see. Unlock the correct answer and full explanation with Pass.
Practice more JEE Physics PYQs
See every question on Electrostatic Potential and Capacitance, or browse the full JEE question bank.
See all questions on Electrostatic Potential and Capacitance →