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For changing the capacitance of a given parallel plate capacitor, a dielectric material of dielectric constant \(K\) is …

Q1

For changing the capacitance of a given parallel plate capacitor, a dielectric material of dielectric constant \(K\) is used, which has the same area as the plates of the capacitor. The thickness of the dielectric slab is \(\frac{3}{4} d\), where ' \(d\) ' is the separation between the plates of parallel plate capacitor.The new capacitance ( \(C^{\prime}\) ) in terms of original capacitance \(\left( C _0\right)\) is given by the following relation:

[JEE Main 2021, 16 Mar (Shift 1)]

a

\(C^{\prime}=\frac{4+K}{3} C_0\)

b

\(C^{\prime}=\frac{3+K}{4 K} C_0\)

c

\(C^{\prime}=\frac{4}{3+K} C_0\)

d

\(C^{\prime}=\frac{4 K}{K+3} C_0\)

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