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The solution curve of the differential equation, \(\left(1+{\mathrm{e}}^{-\mathrm{x}}\right)\left(1+{\mathrm{y}}^{2}\rig…

Q1

The solution curve of the differential equation, \(\left(1+{\mathrm{e}}^{-\mathrm{x}}\right)\left(1+{\mathrm{y}}^{2}\right)\frac{\mathrm{dy}}{\mathrm{dx}}={\mathrm{y}}^{2}\), which passes through the point \((0,1),\) is

[JEE Main 2020, 3 Sep (Shift 1)]

a

\({\text{y}}^{2}+1=\text{y}\left({\log }_{\text{e}}\left(\frac{1+{\text{e}}^{−\text{x}}}{2}\right)+2\right)\)

b

\({\mathrm{y}}^{2}+1=\mathrm{y}\left({\log }_{\mathrm{e}}\left(\frac{1+{\mathrm{e}}^{\mathrm{x}}}{2}\right)+2\right)\)

c

\({\mathrm{y}}^{2}=1+{\mathrm{ylog}}_{\mathrm{e}}\left(\frac{1+{\mathrm{e}}^{-\mathrm{x}}}{2}\right)\)

d

\({\mathrm{y}}^{2}=1+{\mathrm{ylog}}_{\mathrm{e}}\left(\frac{1+{\mathrm{e}}^{\mathrm{x}}}{2}\right)\)

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