A block of mass \(5 kg\) is placed at rest on a table of rough surface. Now, if a force of \(30 N\) is applied in the di…

A block of mass \(5 kg\) is placed at rest on a table of rough surface. Now, if a force of \(30 N\) is applied in the direction parallel to surface of the table, the block slides through a distance of \(50 m\) in an interval of time \(10 s\). Coefficient of kinetic friction is (given, \(g=10 ms ^{-2}\) ):

[JEE Main 2023, 1 Feb (Shift 1)]