🛠️ JEE🧲 Physics

A car of \(800 kg\) is taking turn on a banked road of radius \(300 m\) and angle of banking \(30^{\circ}\). If coeffici…

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A car of \(800 kg\) is taking turn on a banked road of radius \(300 m\) and angle of banking \(30^{\circ}\). If coefficient of static friction is 0.2 then the maximum speed with which car can negotiate the turn safely : \(\left( g =10 m / s ^2, \sqrt{3}=1.73\right)\)

[JEE Main 2024, 06 Apr (Shift 2)]

a

\(264 m / s\)

b

\(51.4 m / s\)

c

\(102.8 m / s\)

d

\(70.4 m / s\)

✓ Correct answer: b)

\(51.4 m / s\)

Explanation

\(\mathrm{m}=800\mathrm{kg}\)
\(\mathrm{r}=300\mathrm{m}\)
\(\theta =30^\circ\)
\({\mu }_{\mathrm{s}}=0.2\)
\({\mathrm{V}}_{\max }=\sqrt{Rg\left[\frac{\tan \theta +\mu }{1-\mu \tan \theta }\right]}\)
\(=\sqrt{300\times \mathrm{g}\times \left[\frac{\tan 30^\circ +0.2}{1-0.2\times \tan 30^\circ }\right]}\)
\(=\sqrt{300\times 10\times \left[\frac{0.57+0.2}{1-0.2\times 0.57}\right]}\)
\({\mathrm{V}}_{\max }=51.4\mathrm{m}/\mathrm{s}\)

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