Laws of Motion
31 JEE Physics previous year questions on Laws of Motion — options free on every question; 3 include the answer & explanation free, the rest unlock with PYQ Pass.
A car of \(800 kg\) is taking turn on a banked road of radius \(300 m\) and angle of banking \(30^{\circ}\). If coefficient of static friction is 0.2 then the maximum speed with which car can negotiate the turn safely : \(\left( g =10 m / s ^2, \sqrt{3}=1.73\right)\)
[JEE Main 2024, 06 Apr (Shift 2)]
\(51.4 m / s\)
\(\mathrm{m}=800\mathrm{kg}\)
\(\mathrm{r}=300\mathrm{m}\)
\(\theta =30^\circ\)
\({\mu }_{\mathrm{s}}=0.2\)
\({\mathrm{V}}_{\max }=\sqrt{Rg\left[\frac{\tan \theta +\mu }{1-\mu \tan \theta }\right]}\)
\(=\sqrt{300\times \mathrm{g}\times \left[\frac{\tan 30^\circ +0.2}{1-0.2\times \tan 30^\circ }\right]}\)
\(=\sqrt{300\times 10\times \left[\frac{0.57+0.2}{1-0.2\times 0.57}\right]}\)
\({\mathrm{V}}_{\max }=51.4\mathrm{m}/\mathrm{s}\)
A massless spring gets elongated by amount \({x}_{1}\) under a tension of 5 N . Its elongation is \({x}_{2}\) under the tension of 7 N . For the elongation of \(\left(5{x}_{1}-2{x}_{2}\right)\), the tension in the spring will be,
[JEE Main 2025, 23 Jan (Shift 2)]
11 N
\({F}_{1}=k{x}_{1}\\ 5=k{x}_{1}\\ {x}_{1}=\frac{5}{k}\\ 7=k{x}_{2}\\ {x}_{2}=\frac{7}{k}\)
\(x=5{x}_{1}-2{x}_{2}\\ x=\frac{25}{k}-\frac{14}{k}\Rightarrow x=\frac{11}{k}\\ F=kx\\ F=k\times \frac{11}{k}\\ F=11N\)
A massless spring gets elongated by amount \({x}_{1}\) under a tension of 5 N . Its elongation is \({x}_{2}\) under the tension of 7 N . For the elongation of \(\left(5{x}_{1}-2{x}_{2}\right)\), the tension in the spring will be,
[JEE Main 2025, 23 Jan (Shift 2)]
11 N
\({F}_{1}=k{x}_{1}\\ 5=k{x}_{1}\\ {x}_{1}=\frac{5}{k}\\ 7=k{x}_{2}\\ {x}_{2}=\frac{7}{k}\)
\(x=5{x}_{1}-2{x}_{2}\\ x=\frac{25}{k}-\frac{14}{k}\Rightarrow x=\frac{11}{k}\\ F=kx\\ F=k\times \frac{11}{k}\\ F=11N\)
A cricket player catches a ball of mass \(120 g\) moving with \(25 m / s\) speed. If the catching process is completed in \(0.1 s\) then the magnitude of force exerted by the ball on the hand of player will be (in SI unit):EndFragment
[JEE Main 2024, 01 Feb (Shift 2)]
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A cricket player catches a ball of mass \(120 g\) moving with \(25 m / s\) speed. If the catching process is completed in \(0.1 s\) then the magnitude of force exerted by the ball on the hand of player will be (in SI unit):EndFragment
[JEE Main 2024, 01 Feb (Shift 2)]
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A massless spring gets elongated by amount \({x}_{1}\) under a tension of 5 N . Its elongation is \({x}_{2}\) under the tension of 7 N . For the elongation of \(\left(5{x}_{1}-2{x}_{2}\right)\), the tension in the spring will be:
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An artillery piece of mass \(M_1\) fires a shell of mass \(M_2\) horizontally. Instantaneously after the firing, the ratio of kinetic energy of the artillery and that of the shell is:
[JEE Main 2024, 31 Jan (Shift 1)]
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An artillery piece of mass \(M_1\) fires a shell of mass \(M_2\) horizontally. Instantaneously after the firing, the ratio of kinetic energy of the artillery and that of the shell is:
[JEE Main 2024, 31 Jan (Shift 1)]
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At \(t=0\), a body of mass 100 g starts moving under the influence of a force \((5\hat{i}+10\hat{j})N\). After 2s its position is \((2x\hat{i}+5y\hat{j})m\). The ratio x: y is ___________ .
[JEE Main 2026, 4 Apr (Shift 2)]
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An object with mass \(500g\) moves along x -axis with speed \(v=4\sqrt{x}\mathrm{m}/\mathrm{s}\). The force acting on the object is :
[JEE Main 2025, 7 Apr (Shift 2)]
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A balloon of mass M is ascending with an acceleration a. What fraction of its mass should be dropped so that it starts moving upward with an acceleration of 3 a ?
(Shift - II Memory Based)
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A balloon of mass M is ascending with an acceleration a. What fraction of its mass should be dropped so that it starts moving upward with an acceleration of 3 a ?
(Shift - II Memory Based)
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Given below are two statements: one is labelled as Assertion (A) and the other is labelled as Reason (R).
Assertion (A): An electric fan continues to rotate for some time after the current is switched off.
Reason (R): Fan continues to rotate due to inertia of motion.
In the light of above statements, choose the most appropriate answer from the options given below.
[JEE Main 2023, 10 Apr (Shift 2)]
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A bullet of mass \(10\mathrm{g}\) leaves the barrel of gun with a velocity of \(600\mathrm{m}/\mathrm{s}\). If the barrel of the gun is \(50\mathrm{cm}\) long and mass of gun is \(3\mathrm{kg}\), then value of impulse supplied to the gun will be:
[JEE Main 2023, 13 Apr (Shift 1)]
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100 balls each of mass \(m\) moving with speed v simultaneously strike a wall normally and are reflected back with the same speed, in time t s. The total force exerted by the balls on the wall is
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A bullet of ' \(4 g\) ' mass is fired from a gun of mass \(4 kg\). If the bullet moves with the muzzle speed of \(50 ms ^{-1}\), the impulse imparted to the gun velocity of recoil of gun are:
[JEE Main 2021, 22 Jul (Shift 2)]
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A machine gun of mass \(10\mathrm{kg}\) fires \(20\mathrm{g}\) bullets at the rate of 180 bullets per minute with a speed of\(100{\mathrm{ms}}^{-1}\) each. The recoil velocity of the gun is:
[JEE Main 2023, 30 Jan (Shift 2)]
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An average force of \(125 \mathrm{~N}\) is applied on a machine gun firing bullets each of mass \(10 \mathrm{~g}\) at the speed of \(250 \mathrm{~m} / \mathrm{s}\) to keep it in position. The number of bullets fired per second by the machine gun is :
[JEE Main 2023, 11 Apr (Shift 1)]
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A particle of mass \(M\) originally at rest is subjected to a force whose direction is constant but magnitude varies with time according to the relation
\(\mathrm{F}=\mathrm{F}_0\left(1-\left(\frac{\mathrm{t}-\mathrm{T}}{\mathrm{T}}\right)^2\right)\)
Where \(F_0\) and \(T\) are constants. The force acts only for the time internal \(2 T\). The velocity \(v\) of the particle after time \(2 T\) is -
[JEE Main 2021, 27 Jul (Shift 2)]
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A bullet of mass \(10\mathrm{g}\) leaves the barrel of gun with a velocity of \(600\mathrm{m}/\mathrm{s}\). If the barrel of the gun is \(50\mathrm{cm}\) long and mass of gun is \(3\mathrm{kg}\), then value of impulse supplied to the gun will be:
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At any instant, the velocity of a particle of mass \(500\mathrm{g}\) is \(\left(2t\hat{i}+3{t}^{2}\hat{j}\right){\mathrm{ms}}^{-1}\). If the force acting on the particle at \(t=1\mathrm{s}\) is \((\hat{i}+x\hat{j})N\). Then the value of x will be:
[JEE Main 2023, 8 Apr (Shift 1)]
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A machine gun of mass \(10\mathrm{kg}\) fires \(20\mathrm{g}\) bullets at the rate of 180 bullets per minute with a speed of\(100{\mathrm{ms}}^{-1}\) each. The recoil velocity of the gun is:
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A force \(\vec{F}=(40\hat{i}+10\hat{j})N\) acts on a body of mass \(5\mathrm{kg}\). If the body starts from rest, its position vector \(\vec{r}\) at time \(t=10\mathrm{s}\), will be:
[JEE Main 2021, 25 Jul (Shift 2)]
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100 balls each of mass \(m\) moving with speed v simultaneously strike a wall normally and are reflected back with the same speed, in time t s. The total force exerted by the balls on the wall is
[JEE Main 2023, 31 Jan (Shift 1)]
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A block of mass \(5 kg\) is placed at rest on a table of rough surface. Now, if a force of \(30 N\) is applied in the direction parallel to surface of the table, the block slides through a distance of \(50 m\) in an interval of time \(10 s\). Coefficient of kinetic friction is (given, \(g=10 ms ^{-2}\) ):
[JEE Main 2023, 1 Feb (Shift 1)]
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A particle of mass \(M\) originally at rest is subjected to a force whose direction is constant but magnitude varies with time according to the relation
\(\mathrm{F}=\mathrm{F}_0\left(1-\left(\frac{\mathrm{t}-\mathrm{T}}{\mathrm{T}}\right)^2\right)\)
Where \(F_0\) and \(T\) are constants. The force acts only for the time internal \(2 T\). The velocity \(v\) of the particle after time \(2 T\) is -
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The time taken by an object to slide down a \(45^{\circ}\) rough inclined plane is \(n\) times as it takes to slide down a perfectly smooth \(45^{\circ}\) inclined plane. The coefficient of kinetic friction between the object and the incline plane is
[JEE Main 2024, 08 Apr (Shift 2)]
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A particle of mass m is moving in the x y-plane such that its velocity at a point (x, y) is given as \(\vec{v}=\alpha (y\hat{x}+2x\hat{y})\), where \(\alpha\) is a non-zero constant. What is the force \(\vec{F}\) acting on the particle?
[JEE Advanced 2023]
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An average force of 125 N is applied on a machine gun firing bullets each of mass 10g at the speed of 250 m/s to keep it in position. The number of bullets fired per second by the machine gun is :
[JEE Main 2023, 11 Apr (Shift 1)]
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Given below are two statements: one is labelled as Assertion (A) and the other is labelled as Reason (R).
Assertion (A): An electric fan continues to rotate for some time after the current is switched off.
Reason (R): Fan continues to rotate due to inertia of motion.
In the light of above statements, choose the most appropriate answer from the options given below.
Options are free to see. Unlock the correct answer and full explanation with Pass.
A body of mass \(500 \mathrm{~g}\) moves along \(\mathrm{x}\)-axis such that it's velocity varies with displacement \(x\) according to the relation \(v=10 \sqrt{x} \mathrm{~m} / \mathrm{s}\) the force acting on the body is:-
[JEE Main 2023, 11 Apr (Shift 2)]
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