The molarity of the solution prepared by dissolving \( 6.3 \mathrm{~g} \) of oxalic acid \( \left(\mathrm{H}_{2} \mathrm{C}_{2} \mathrm{O}_{4} \cdot 2 \mathrm{H}_{2} \mathrm{O}\right) \) in \( 250 \mathrm{~mL} \) of water in \( \mathrm{molL}^{-1} \) is \( \mathrm{x} \times 10^{-2} \). The value of \( \mathrm{x} \) is (Nearest integer) [Atomic mass: \( \mathrm{H}: 1.0, \mathrm{C}: 12.0,0: 16.0 \) ]

[JEE Main 2021, 31 Aug (Shift 1)]

Question

The molarity of the solution prepared by dissolving \( 6.3 \mathrm{~g} \) of oxalic acid \( \left(\mathrm{H}_{2} \mathrm{C}_{2} \mathrm{O}_{4} \cdot 2 \mathrm{H}_{2} \mathrm{O}\right) \) in \( 250 \mathrm{~mL} \) of water in \( \mathrm{molL}^{-1} \) is \( \mathrm{x} \times 10^{-2} \). The value of \( \mathrm{x} \) is (Nearest integer) [Atomic mass: \( \mathrm{H}: 1.0, \mathrm{C}: 12.0,0: 16.0 \) ]

[JEE Main 2021, 31 Aug (Shift 1)]

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