🛠️ JEE🧪 Chemistry

Identify the mixture that shows positive deviations from Raoult's Law

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Identify the mixture that shows positive deviations from Raoult's Law
aCHCl3 + (CH3)2CO
b(CH3)2CO + C6H5NH2
c(CH3)2CO + CS2
dCHCl3 + C6H6
✓ Correct answer: c) (CH3)2CO + CS2
ExplanationMixing polar acetone with non-polar CS₂ weakens intermolecular attractions (A–B < A– A/B–B) → positive deviation from Raoult’s law.The other pairs (acetone–chloroform, acetone– aniline, chloroform–benzene) form specific associations/H-bonding → negative deviation.

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