What is the freezing point depression constant of a solvent 50 g of which contain 1 g of non-volatile solute(M.W: 256 g/…

\(\mathrm{Depression}\mathrm{in}\mathrm{freezing}\mathrm{point}∆{\mathrm{T}}_{\mathrm{b}}={\mathrm{K}}_{\mathrm{f}}.\mathrm{m}\\ \mathrm{molality}\mathrm{m}=\frac{1}{256}\times \frac{1000}{50}=0.0781\\ {\mathrm{K}}_{\mathrm{f}}=\frac{∆{\mathrm{T}}_{\mathrm{b}}}{\mathrm{m}}=0.4/0.0781=5.12\mathrm{KKg}/\mathrm{mol}\)