In a 3M aqueous solution of NaCl, having density 1.25 g/ml, what will be the molality of the solution?
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In a 3M aqueous solution of NaCl, having density 1.25 g/ml, what will be the molality of the solution?
✓ Correct answer: c)
2.79
Explanation
\(molality(m)=\frac{1000M}{1000d-M\times {M}_{0}}(whereM=molarity,{M}_{0}=molarmass)\\ m=\frac{3000}{1250-58.5\times 3}=2.79\)
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