🛠️ JEE➗ Maths

If \({\mathrm{x}}^{3}\mathrm{dy}+\mathrm{xydx}={\mathrm{x}}^{2}\mathrm{dy}+2\mathrm{ydx};\mathrm{y}(2)=\mathrm{e}\) and …

Q1

If \({\mathrm{x}}^{3}\mathrm{dy}+\mathrm{xydx}={\mathrm{x}}^{2}\mathrm{dy}+2\mathrm{ydx};\mathrm{y}(2)=\mathrm{e}\) and \(x > 1,\) then \(y(4)\) is equal to:

[JEE Main 2020, 3 Sep (Shift 2)]

a

\(\frac{\sqrt{\mathrm{e}}}{2}\)

b

\(\frac{1}{2}+\sqrt{\mathrm{e}}\)

c

\(\frac{3}{2}+\sqrt{\mathrm{e}}\)

d

\(\frac{3}{2}\sqrt{\mathrm{e}}\)

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