\( 224 \mathrm{~mL} \) of \( \mathrm{SO}_{2(\mathrm{~g})} \) at \( 298 \mathrm{~K} \) and \( 1 \mathrm{~atm} \) is passe…

\( 224 \mathrm{~mL} \) of \( \mathrm{SO}_{2(\mathrm{~g})} \) at \( 298 \mathrm{~K} \) and \( 1 \mathrm{~atm} \) is passed through \( 100 \mathrm{~mL} \) of \( 0.1 \mathrm{~M} \mathrm{~NaOH} \) solution. The non-volatile solute produced is dissolved in \( 36 \mathrm{~g} \) of water. The lowering of vapour pressure of solution (assuming the solution is dilute) \( \left(\mathrm{P}_{\left(\mathrm{H}_{2} \mathrm{O}\right)}^{\mathrm{O}}=24 \mathrm{~mm}\right. \) of \( \left.\mathrm{Hg}\right) \) is \( \mathrm{x} \times 10^{-2} \mathrm{~mm} \) of \( \mathrm{Hg} \), the value of \( \mathrm{x} \) is ...... (Integer answer)

[JEE Main 2021, 26 Feb (Shift 1)]