Let $ \alpha, \beta $ be two roots of the equation $ x^{2}+(20)^{\frac{1} { 4}} x+(5)^{\frac{1} {2}}=0 $. Then $ \alpha^{8}+\beta^{8} $ is equal to [JEE Main 2021, 27 Jul (Shift 1)]

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Let \( \alpha, \beta \) be two roots of the equation \( x^{2}+(20)^{\frac{1} { 4}} x+(5)^{\frac{1} {2}}=0 \). Then \( \a…

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