If the quadratic equation \((\lambda +2){\mathrm{x}}^{2}-3\mathrm{λx}+4\lambda =0,\lambda \neq -2\), has two positive ro…
If the quadratic equation \((\lambda +2){\mathrm{x}}^{2}-3\mathrm{λx}+4\lambda =0,\lambda \neq -2\), has two positive roots, then the number of possible integral values of \(\lambda\) is:
[JEE Main 2026, 4 Apr (Shift 2)]
\(2\)
\( f(x)=(\lambda+2) x^2-3 \lambda x+4 \lambda\)
Case - 1: \(\frac{c}{a}>0\) or \(a c>0\)
\( (\lambda+2) 4 \lambda>0\)
\( \Rightarrow \lambda<-2 \text { or } \lambda>0\)
Case - 2: \(-\frac{\mathrm{b}}{2 \mathrm{a}}>0 \)
\( \frac{3 \lambda}{2(\lambda+2)}>0 \)
\( \Rightarrow \lambda<-2 \text { or } \lambda>0\)
Case - 3: \(\mathrm{D} \geq 0\)
\( (-3 \lambda)^2-4(\lambda+2) \times 4 \lambda \geq 0 \)
\( \lambda(7 \lambda+32) \leq 0 \)
\( \Rightarrow \lambda \in\left[\frac{-32}{7}, 0\right]\)
Intersection of Case-1, Case-2 and Case-3
\( \Rightarrow \lambda \in\left[\frac{-32}{7},-2\right)\)
\( \Rightarrow \lambda \in[-4.57,-2)\)
\( \Rightarrow \lambda=-4,-3\)
Number of values of \(\lambda=2\)
Practice more JEE Maths PYQs
See every question on Quadratic Equations, or browse the full JEE question bank.
See all questions on Quadratic Equations →