🛠️ JEE➗ Maths

If x, y and z are real numbers, then \({x}^{2}+4{y}^{2}+9{z}^{2}−6yz−3zx−2xy\) is always

Q1

If x, y and z are real numbers, then

\({x}^{2}+4{y}^{2}+9{z}^{2}−6yz−3zx−2xy\) is always

a

positive

b

non-positive

c

zero

d

non-negative

🔒
Answer & explanation — PYQ Pass

Options are free to see. Unlock the correct answer and full explanation with Pass.

Unlock · ₹149

Practice more JEE Maths PYQs

See every question on Quadratic Equations, or browse the full JEE question bank.

See all questions on Quadratic Equations →