\(4.5 g\) of compound \(A(M W=90)\) was used to make \(250 ~mL\) of its aqueous solution. The molarity of the solution i…

\(4.5 g\) of compound \(A(M W=90)\) was used to make \(250 ~mL\) of its aqueous solution. The molarity of the solution in \(M\) is \(x \times 10^{-1}\). The value of \(x\) is (Rounded off to the nearest integer)

[JEE Main 2021, 24 Feb (Shift 1)]