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Let x = x ( y ) be the solution of the differential equation 2( y + 2)log e ( y + 2) dx + ( x + 4–2log e ( y + 2)) dy = …

Q1

Let x = x(y) be the solution of the differential equation 2(y + 2)loge (y + 2)dx + (x + 4–2loge (y + 2))dy = 0, y > –1 with x(e4–2) = 1. Then x(e9–2) is equal to

[JEE Main 2023, 15 Apr (Shift 1)]

a

\(\frac{4}{9}\)

b

\(\frac{10}{3}\)

c

\(\frac{32}{9}\)

d

3

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