🛠️ JEE🧲 Physics

A force \( \vec{F}=(\hat{i}+2 \hat{j}+3 \hat{k}) N \) acts at a point \( (4 \hat{i}+3 \hat{j}-\hat{k}) m \). Then the ma…

Q1

A force \( \vec{F}=(\hat{i}+2 \hat{j}+3 \hat{k}) N \) acts at a point \( (4 \hat{i}+3 \hat{j}-\hat{k}) m \). Then the magnitude of torque about the point \( (\hat{i}+2 \hat{j}+\hat{k}) \) \( m \) will be \( \sqrt{x} N-m \). The value of \( x \) is

[JEE Main 2020, 5 Sep (Shift 1)]

a

195

b

165

c

105

d

135

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