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Which of the following are correct expressions for torque acting on a body? A. \(\vec{\tau }=\vec{\mathrm{r}}\times \vec…

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Which of the following are correct expressions for torque acting on a body?
A. \(\vec{\tau }=\vec{\mathrm{r}}\times \vec{\mathrm{L}}\)
B. \(\vec{\tau }=\frac{\mathrm{d}}{\mathrm{dt}}(\vec{\mathrm{r}}\times \vec{\mathrm{p}})\)
C. \(\vec{\tau }=\vec{\mathrm{r}}\times \frac{\mathrm{d}\vec{\mathrm{p}}}{\mathrm{dt}}\)
D. \(\vec{\tau }=\mathrm{I}\vec{\alpha }\)
E. \(\vec{\tau }=\vec{\mathrm{r}}\times \vec{\mathrm{F}}\)
( \(\vec{\mathrm{r}}=\) position vector; \(\vec{\mathrm{p}}=\) linear momentum; \(\vec{\mathrm{L}}=\)angular momentum; \(\vec{\alpha }=\)angular acceleration; \(\mathrm{I}=\)moment of inertia; \(\vec{\mathrm{F}}=\) force; \(\mathrm{t}=\) time)
Choose the correct answer from the options given below :

[JEE Main 2025, 4 Apr (Shift 1)]

a

B, D and E Only

b

C and D Only

c

B, C, D and E Only

d

B, C, D and E Only

✓ Correct answer: c)

B, C, D and E Only

Explanation

\(\vec{\tau }=\vec{r}\times \vec{L}\)
This relation is incorrect in general because torque is not the cross product of position vector and angular momentum.

\(\vec{\tau }=\frac{d}{dt}\left(\vec{r}\times \vec{p}\right)\)
This is correct and represents the fundamental definition of torque.
Using Newton’s second law, the time derivative of momentum equals force.
\(\vec{\tau }=\vec{r}\times \frac{d\vec{p}}{dt}=\vec{r}\times \vec{F}\)
This form is correct and commonly used in mechanics.

\(\vec{\tau }=I\vec{\alpha }\)
This relation is correct for rigid bodies rotating about a fixed axis.

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