A solid sphere is rolling without slipping on a horizontal plane. The ratio of the linear kinetic energy of the centre o…

Required ratio \(=\frac{\frac{1}{2}m{v}^{2}}{\frac{1}{2}I{\omega }^{2}}\)

Using \((V=\omega R)\), we get

\(=\frac{\frac{1}{2}m(\omega R{)}^{2}}{\frac{1}{2}\times \frac{2}{5}m{R}^{2}\times {\omega }^{2}}=\frac{5}{2}\)