🛠️ JEE➗ Maths

Let y = y(x) be the solution of the differential equation \(\frac{\mathrm{dy}}{\mathrm{dx}}=1+{\mathrm{xe}}^{\mathrm{y}-…

Q1

Let y = y(x) be the solution of the differential equation \(\frac{\mathrm{dy}}{\mathrm{dx}}=1+{\mathrm{xe}}^{\mathrm{y}-\mathrm{x}},-\sqrt{2}<\mathrm{x}<\sqrt{2},\mathrm{y}(0)=0\) then, the minimum value of \(\mathrm{y}(\mathrm{x}),\mathrm{x}\in (-\sqrt{2},\sqrt{2})\) is equal to:

[JEE Main 2021, 25 Jul (Shift 1)]

a

\((1+\sqrt{3})-{\log }_{\mathrm{e}}(\sqrt{3}-1)\)

b

\((2+\sqrt{3})+{\log }_{\mathrm{e}}2\)

c

\((1-\sqrt{3})-{\log }_{\mathrm{e}}(\sqrt{3}-1)\)

d

\((2-\sqrt{3})-{\log }_{e}2\)

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