YESPYQ Start Practice
🛠️ JEE➗ Maths

Let \(y=y(x)\) be the solution of the differential equation \(\frac{d y}{d x}=\left(1+x+x^2\right)\left(1-y+y^2\right), …

Q1

Let \(y=y(x)\) be the solution of the differential equation \(\frac{d y}{d x}=\left(1+x+x^2\right)\left(1-y+y^2\right), y(0)=\frac{1}{2}\) then \((2y(1)-1)\) is equal to:

[JEE Main 2026, 4 Apr (Shift 1)]

a

\(\sqrt{3}\tan \left(\frac{11\sqrt{3}}{6}\right)\)

b

\(\frac{\sqrt{3}}{2}\tan \left(\frac{11\sqrt{3}}{12}\right)\)

c

\(\sqrt{3}\tan \left(\frac{11\sqrt{3}}{12}\right)\)

d

\(\frac{\sqrt{3}}{2}\tan \left(\frac{11\sqrt{3}}{6}\right)\)

🔒
Answer & explanation — PYQ Pass

Options are free to see. Unlock the correct answer and full explanation with Pass.

Unlock · ₹149
← Previous questionNext question →

Practice more JEE Maths PYQs

See every question on Differential Equations, or browse the full JEE question bank.

See all questions on Differential Equations →