🛠️ JEE➗ Maths

Let \(y=y(x)\) be the solution of the differential equation \(\frac{dy}{dx}+3\left({\tan }^{2}x\right)y+3y={\sec }^{2}x\…

Q1

Let \(y=y(x)\) be the solution of the differential equation \(\frac{dy}{dx}+3\left({\tan }^{2}x\right)y+3y={\sec }^{2}x\), \(y(0)=\frac{1}{3}+{e}^{3}\). Then \(y\left(\frac{\pi }{4}\right)\) is equal to

[JEE Main 2025, 3 Apr (Shift 2)]

a

\(\frac{2}{3}\)

b

\(\frac{4}{3}\)

c

\(\frac{4}{3}+{e}^{3}\)

d

\(\frac{2}{3}+{\mathrm{e}}^{3}\)

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