A particle is rotating in a circular path and at any instant its motion can be described as \(\theta =\frac{5{t}^{4}}{40}-\frac{{t}^{3}}{3}\) The angular acceleration of the particle after 10 seconds is __________________ \(rad/{s}^{2}\).

[JEE Main 2026, 2 Apr (Shift 1)]

Question

A particle is rotating in a circular path and at any instant its motion can be described as \(\theta =\frac{5{t}^{4}}{40}-\frac{{t}^{3}}{3}\) The angular acceleration of the particle after 10 seconds is __________________ \(rad/{s}^{2}\).

[JEE Main 2026, 2 Apr (Shift 1)]

YESPYQ · Accepted Answer

Options are free to see. Unlock the correct answer and full explanation with PYQ Pass.

A particle is rotating in a circular path and at any instant its motion can be described as \(\theta =\frac{5{t}^{4}}{40…

Practice more JEE Physics PYQs