A solution containing 10 g of an electrolyte in 100 g of water boils at \(100.52{}^{\mathrm{o}}\mathrm{C}\). The degree …
Q1
A solution containing 10 g of an electrolyte in 100 g of water boils at \(100.52{}^{\mathrm{o}}\mathrm{C}\). The degree of ionization of the electrolyte is \(x\times {10}^{-1}\) (nearest integer)
[Given : Molar mass of \(AB _2=200 ~g mol ^{-1}, K _{ b }\) (molal boiling point elevation const. of water) \(=0.52 ~K kg mol ^{-1}\), boiling point of water \(=100^{\circ} C ; AB _2\) ionises as \(\left.AB _2 \rightarrow A ^{2+}+2 B ^{-}\right]\)
[JEE Main 2024, 08 Apr (Shift 1)]
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