In a group of 3 girls and 4 boys, there are two boys ${B}_{1}and{B}_{2}$. The number of ways, in which these girls and boys can stand in a queue such that all the girls stand together, all the boys stand together, but ${B}_{1}and{B}_{2}$ are not adjacent to each other, is :

[JEE Main 2025, 22 Jan (Shift 2)]

Question

In a group of 3 girls and 4 boys, there are two boys ${B}_{1}and{B}_{2}$. The number of ways, in which these girls and boys can stand in a queue such that all the girls stand together, all the boys stand together, but ${B}_{1}and{B}_{2}$ are not adjacent to each other, is :

[JEE Main 2025, 22 Jan (Shift 2)]

YESPYQ · Accepted Answer

Correct answer: a) 144. $\text{Required number of ways}=\ \text{Total ways}-\text{ways in which}{\mathrm{B}}_{1}\text{and}{\mathrm{B}}_{2}\text{are together}\ =2!(3!4!)-2!(3!(3!2!))=144$

In a group of 3 girls and 4 boys, there are two boys \({B}_{1}and{B}_{2}\). The number of ways, in which these girls and…

Practice more JEE Maths PYQs