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Two point charges \({q}_{1}=3\mu C\) and \({q}_{2}=-4\mu C\) are placed at points \((2\hat{i}+3\hat{j}+3\hat{k})\) and \…

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Two point charges \({q}_{1}=3\mu C\) and \({q}_{2}=-4\mu C\) are placed at points \((2\hat{i}+3\hat{j}+3\hat{k})\) and \((\hat{i}+\hat{j}+\hat{k})\) respectively. Force on charge \({q}_{2}\) is _________ N. (Take \(\frac{1}{4\pi {ϵ}_{0}}=9\times {10}^{9}\) SI Units)

[JEE Main 2026, 8 Apr (Shift 2)]

a

\((12\hat{i}+24\hat{j}+24\hat{k})\times {10}^{-3}\)

b

\((4\hat{i}+8\hat{j}+8\hat{k})\times {10}^{-3}\)

c

\((3\hat{i}+6\hat{j}+6\hat{k})\times {10}^{-3}\)

d

\((-4\hat{i}-8\hat{j}-8\hat{k})\times {10}^{-3}\)

✓ Correct answer: b)

\((4\hat{i}+8\hat{j}+8\hat{k})\times {10}^{-3}\)

Explanation

Vector from \({q}_{1}\) to \({q}_{2}\) :

\(\vec{r}={\vec{r}}_{2}-{\vec{r}}_{1}=-\hat{i}-2\hat{j}-2\hat{k}\)

Distance: \(r=\sqrt{1+4+4}=3\)
Force on \({q}_{2}\) :

\(\vec{F}=\frac{1}{4\pi {\epsilon }_{0}}\frac{{q}_{1}{q}_{2}}{{r}^{3}}\vec{r}\)

Since \({q}_{1}=3\mu C\) and \({q}_{2}=-4\mu C\), the force is attractive, hence along

\(\hat{i}+2\hat{j}+2\hat{k}\)

\(\Rightarrow \frac{9\times {10}^{9}\times (3)(4)\times {10}^{-12}}{27}(\hat{i}+2\hat{j}+2\hat{k})\)

\(\Rightarrow 4\times {10}^{-3}[\hat{i}+2\hat{j}+2\hat{k}]\)

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