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Consider a circular loop that is uniformly charged and has a radius \(\mathrm{a}\sqrt{2}\). Find the position along the …

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Consider a circular loop that is uniformly charged and has a radius \(\mathrm{a}\sqrt{2}\). Find the position along the positive z -axis of the cartesian coordinate system where the electric field is maximum if the ring was assumed to be placed in xy-plane at the origin :

[JEE Main 2025, 2 Apr (Shift 2)]

a

\(\frac{a}{\sqrt{2}}\)

b

\(\frac{a}{2}\)

c

\(a\)

d

\(0\)

✓ Correct answer: c)

\(a\)

Explanation

$$
\begin{aligned}
& E=\frac{K Q r}{\left(x^2+R^2\right)^{\frac{3}{2}}} \\
& \frac{d E}{d x}=0 \\
& \therefore x=\frac{R}{\sqrt{2}}=\frac{\sqrt{2 a}}{\sqrt{2}}=a
\end{aligned}
$$

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