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The correct increasing order of spin only magnetic moment values of the complex ions \(\text{ }{\left[{\mathrm{MnBr}}_{4…

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The correct increasing order of spin only magnetic moment values of the complex ions \(\text{ }{\left[{\mathrm{MnBr}}_{4}\right]}^{2−}\left(\mathrm{A}\right),\text{ }{\left[\mathrm{Cu}\left({\mathrm{H}}_{2}{\mathrm{O}}_{6}\right)\right]}^{2+}\text{ }\left(\mathrm{B}\right),\text{  }{\left[\mathrm{Ni}{\left(\mathrm{CN}\right)}_{4}\right]}^{2−}\text{ }\)(C) and \(\text{ }{\left[\mathrm{Ni}{\left({\mathrm{H}}_{2}\mathrm{O}\right)}_{6}\right]}^{2+}\left(\mathrm{D}\right)\) is:

[JEE Main 2026, 28 Jan (Shift 2)]

a

C = D < B < A

b

C < B < D < A

c

A = B < C < D

d

A = B < D < C

✓ Correct answer: b)

C < B < D < A

Explanation

(C) [Ni(CN)₄]²⁻

Ni²⁺ → 3d⁸

CN⁻ = strong field ligand → pairing occurs

Structure: square planar

Unpaired electrons = 0

(B) [Cu(H₂O)₆]²⁺

Cu²⁺ → 3d⁹

Unpaired electrons = 1

(D) [Ni(H₂O)₆]²⁺

Ni²⁺ → 3d⁸

H₂O = weak field → no pairing

Unpaired electrons = 2

(A) [MnBr₄]²⁻

Mn²⁺ → 3d⁵

Br⁻ = weak field

Tetrahedral → no pairing

Unpaired electrons = 5

Order (increasing)

C (0) < B (1) < D (2) < A (5)

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