Match List-I with List-II: List-I List-II (A) ${\left[{\mathrm{CoF}}_{6}\right]}^{3-}$ (I) ${\mathrm{sp}}^{3}{\mathrm{d}}^{2}$ (B) ${\left[\mathrm{Co}{\left({\mathrm{NH}}_{3}\right)}_{6}\right]}^{3+}$ (II) ${\mathrm{d}}^{2}{\mathrm{sp}}^{3}$ (C) ${\left[{\mathrm{NiCl}}_{4}\right]}^{2-}$ (III) ${\mathrm{sp}}^{3}$ (D) ${\left[\mathrm{Ni}{\left(\mathrm{CN}\right)}_{4}\right]}^{2-}$ (IV) ${\mathrm{dsp}}^{2}$ Choose the correct answer from the options given below:

Question

YESPYQ · Accepted Answer

Correct answer: a) A-I, B-II, C-III, D-IV. To determine hybridization, we consider oxidation state, ligand strength, and geometry. [CoF₆]³⁻ has Co³⁺ (d⁶) with fluoride as a weak field ligand, leading to a high-spin octahedral complex with sp³d² hybridization. [Co(NH₃)₆]³⁺ has Co³⁺ (d⁶) with ammonia as a strong field ligand, forming a low-spin octahedral complex with d²sp³ hybridization. [NiCl₄]²⁻ has Ni²⁺ (d⁸) with chloride as a weak field ligand, resulting in a tetrahedral complex with sp³ hybridization. [Ni(CN)₄]²⁻ has Ni²⁺ (d⁸) with cyanide as a strong field ligand, forming a square planar complex with dsp² hybridization. The correct answer is option (1).

List-I	List-II
(A)	\({\left[{\mathrm{CoF}}_{6}\right]}^{3-}\)	(I)	\({\mathrm{sp}}^{3}{\mathrm{d}}^{2}\)
(B)	\({\left[\mathrm{Co}{\left({\mathrm{NH}}_{3}\right)}_{6}\right]}^{3+}\)	(II)	\({\mathrm{d}}^{2}{\mathrm{sp}}^{3}\)
(C)	\({\left[{\mathrm{NiCl}}_{4}\right]}^{2-}\)	(III)	\({\mathrm{sp}}^{3}\)
(D)	\({\left[\mathrm{Ni}{\left(\mathrm{CN}\right)}_{4}\right]}^{2-}\)	(IV)	\({\mathrm{dsp}}^{2}\)

Match List-I with List-II: List-I List-II (A) \({\left[{\mathrm{CoF}}_{6}\right]}^{3-}\) (I) \({\mathrm{sp}}^{3}{\mathrm…

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