Correct statements for an element with atomic number 9 are (A). There can be 5 electrons for which \({\mathrm{m}}_{\math…
Correct statements for an element with atomic number 9 are
(A). There can be 5 electrons for which \({\mathrm{m}}_{\mathrm{s}}=+\frac{1}{2}\) and 4 electrons for which \({\mathrm{m}}_{\mathrm{s}}=-\frac{1}{2}\)
(B). There is only one electron in \({p}_{z}\)orbital
(C). The last electron goes to orbital with \(\mathrm{n}=2\) and \(l=1\)
(D). The sum of angular nodes of all the atomic orbitals is 1 .
Choose the correct answer from the options given below:
(A) and (C) only
\(\mathrm{F}(\mathrm{Z}=9)\\ 1{\mathrm{s}}^{2}2{\mathrm{s}}^{2}2{\mathrm{p}}^{5}\\ \mathrm{number}\mathrm{of}\mathrm{electrons}\mathrm{with}\mathrm{s}=+1/2,\mathrm{is}5\\ \mathrm{number}\mathrm{of}\mathrm{electrons}\mathrm{with}\mathrm{s}=-1/2,\mathrm{is}4\\ \mathrm{Sum}\mathrm{of}\mathrm{angular}\mathrm{nodes}\mathrm{of}\mathrm{all}\mathrm{orbitals}=0+0+1+1+1=3\\\)
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