The maximum number of orbitals which can be identified with \(\mathrm{n}=4\) and \({m}_{l}=0\) is _______

For n = 4, the possible values of azimuthal quantum number l are 0, 1, 2, and 3. For each value of l, the magnetic quantum number mₗ can have values from −l to +l. Since mₗ = 0 is possible for every value of l, one orbital is obtained from each l value. Therefore, the total number of orbitals corresponding to n = 4 and mₗ = 0 is 4. Hence, the correct answer is Option D (4).

4s- 1 orbital

4p- 1 orbital

4d- 1 orbital

4f- 1 orbital