Volume of M/8 \(KMn{O}_{4}\) solution required to react completely with 25.0 \(c{m}^{3}\) of M/4 \(FeS{O}_{4}\) in acidi…

The reaction is

\({\mathrm{MnO}}_{4}^{-}\) + 5Fe²⁺ + 8H⁺ → Mn²⁺ + 5Fe³⁺ + 4H₂O.

Using N₁V₁ = N₂V₂,

\(\frac{1}{8}\times 5{V}_{1}=\frac{1}{4}\times 25\)

Solving, V₁ = 10 mL.