A survey shows that 63% of the people in a city read newspaper A whereas 76% read newspaper B . If x % of the people rea…

Let the total number of people in the city be \( 100 \).

Also, let \( A \) denotes the set of people who read

newspaper \( A \) and \( B \) denotes the set of people who

read newspaper \( B \).

\[ n(A)=63, n(B)=76 \]

Clearly, \( n(A \cup B) \) Clearly

\[ \begin{aligned} & \Rightarrow \quad n(A)+n(B)-n(A \cap B) \leq 100 \\ & \Rightarrow \quad 63+76-x \leq 100 \Rightarrow x \geq 39 \\ & \text { Also, } x \leq 63 \quad \therefore 39 \leq x \leq 63 \end{aligned} \]

Also, \( x \leq 63 \quad \therefore 39 \leq x \leq 63 \)

So, the possible value of \( x \) can be \( 55 \).